(1/x)+(3/2x)=1

Solution for (1/x)+(3/2x)=1 equation:

(1/x)+(3/2x)=1

We move all terms to the left:

(1/x)+(3/2x)-(1)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/x)+(+3/2x)-1=0

We get rid of parentheses

1/x+3/2x-1=0

We calculate fractions


2x/2x^2+3x/2x^2-1=0

We multiply all the terms by the denominator


2x+3x-1*2x^2=0

We add all the numbers together, and all the variables

5x-1*2x^2=0

Wy multiply elements

-2x^2+5x=0

a = -2; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-2)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-2}=\frac{-10}{-4}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-2}=\frac{0}{-4}
=0
$