(1/x)+(1/y)=1

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Solution for (1/x)+(1/y)=1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/y = 1 // - 1

1/x+1/y-1 = 0

1*x^-1 = -(y^-1-1) // : 1

x^-1 = 1-y^-1

-1 < 0

1/(x^1) = 1-y^-1 // * x^1

1 = x^1*(1-y^-1) // : 1-y^-1

1/(1-y^-1) = x^1

x = 1/(1-y^-1)

x = 1/(1-y^-1)

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