(1/x)+(1/x+4)=1/3

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Solution for (1/x)+(1/x+4)=1/3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x+4 = 1/3 // - 1/3

1/x+1/x-(1/3)+4 = 0

1/x+1/x-1/3+4 = 0

2*x^-1 = -11/3 // : 2

x^-1 = -11/6

-1 < 0

1/(x^1) = -11/6 // * x^1

1 = -11/6*x^1 // : -11/6

-6/11 = x^1

x = -6/11

x = -6/11

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