(1/x)+(1/2x)=3/4

Solution for (1/x)+(1/2x)=3/4 equation:

(1/x)+(1/2x)=3/4

We move all terms to the left:

(1/x)+(1/2x)-(3/4)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/x)+(+1/2x)-(+3/4)=0

We get rid of parentheses

1/x+1/2x-3/4=0

We calculate fractions


(-12x^2)/32x^2+32x/32x^2+16x/32x^2=0

We multiply all the terms by the denominator


(-12x^2)+32x+16x=0

We add all the numbers together, and all the variables

(-12x^2)+48x=0

We get rid of parentheses

-12x^2+48x=0

a = -12; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-12)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-12}=\frac{-96}{-24}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-12}=\frac{0}{-24}
=0
$