(1/w-3)-(1/3w-9)=(2/3w-9)

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Solution for (1/w-3)-(1/3w-9)=(2/3w-9) equation:


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((1/3)*w)-3+9 = (2/3)*w-9 // - (2/3)*w-9

1/w-((1/3)*w)-((2/3)*w)-3+9+9 = 0

(-1/3)*w+(-2/3)*w+1/w-3+9+9 = 0

1*w^-1-1*w^1+15*w^0 = 0

(15*w^1-1*w^2+1*w^0)/(w^1) = 0 // * w^2

w^1*(15*w^1-1*w^2+1*w^0) = 0

w^1

15*w-w^2+1 = 0

15*w-w^2+1 = 0

DELTA = 15^2-(-1*1*4)

DELTA = 229

DELTA > 0

w = (229^(1/2)-15)/(-1*2) or w = (-229^(1/2)-15)/(-1*2)

w = (229^(1/2)-15)/(-2) or w = (229^(1/2)+15)/2

w in { (229^(1/2)-15)/(-2), (229^(1/2)+15)/2}

w in { (229^(1/2)-15)/(-2), (229^(1/2)+15)/2 }

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