(1/p-2)-(2/4p+3)

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Solution for (1/p-2)-(2/4p+3) equation: 


D( p )

p = 0

p = 0

p = 0

p in (-oo:0) U (0:+oo)

1/p-((2/4)*p)-3-2 = 0

(-1/2)*p+1/p-3-2 = 0

1*p^-1-1/2*p^1-5*p^0 = 0

(1*p^0-1/2*p^2-5*p^1)/(p^1) = 0 // * p^2

p^1*(1*p^0-1/2*p^2-5*p^1) = 0

p^1

(-1/2)*p^2-5*p+1 = 0

(-1/2)*p^2-5*p+1 = 0

DELTA = (-5)^2-(1*4*(-1/2))

DELTA = 27

DELTA > 0

p = (27^(1/2)+5)/(2*(-1/2)) or p = (5-27^(1/2))/(2*(-1/2))

p = -(3*3^(1/2)+5) or p = -(5-3*3^(1/2))

p in { -(3*3^(1/2)+5), -(5-3*3^(1/2))} 

p in { -(3*3^(1/2)+5), -(5-3*3^(1/2)) }

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