(1/d-1/3)/(d-3)

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Solution for (1/d-1/3)/(d-3) equation: 


D( d )

d = 0

d-3 = 0

d = 0

d = 0

d-3 = 0

d-3 = 0

d-3 = 0 // + 3

d = 3

d in (-oo:0) U (0:3) U (3:+oo)

(1/d-(1/3))/(d-3) = 0

(1/d-1/3)/(d-3) = 0

(d^-1-1/3)/(d-3) = 0

1*d^-1 = 1/3 // : 1

d^-1 = 1/3

-1 < 0

1/(d^1) = 1/3 // * d^1

1 = 1/3*d^1 // : 1/3

3 = d^1

d = 3

d in { 3} 

d belongs to the empty set

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