(1/8c+16)-(3/8+3c)=0

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Solution for (1/8c+16)-(3/8+3c)=0 equation: 



(1/8c+16)-(3/8+3c)=0



Domain of the equation: 8c+16)!=0

c∈R





Domain of the equation: 8+3c)!=0

We move all terms containing c to the left, all other terms to the right

3c)!=-8

c!=-8/1

c!=-8

c∈R



We add all the numbers together, and all the variables

(1/8c+16)-(+3c+3/8)=0

We get rid of parentheses

1/8c-3c+16-3/8=0

We calculate fractions


-3c+16=0

We move all terms containing c to the left, all other terms to the right

-3c=-16

c=-16/-3

c=5+1/3

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