(1/8)+(3/4)x=1(7/8)

Solution for (1/8)+(3/4)x=1(7/8) equation:

(1/8)+(3/4)x=1(7/8)

We move all terms to the left:

(1/8)+(3/4)x-(1(7/8))=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)x+(+1/8)-(1(+7/8))=0

We multiply parentheses

3x^2+(+1/8)-(1(+7/8))=0

We get rid of parentheses

3x^2+1/8-(1(+7/8))=0

We calculate fractions


3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$