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(1/7x+5)=(x/x+1)
We move all terms to the left:
(1/7x+5)-((x/x+1))=0
Domain of the equation: 7x+5)!=0
x∈R
Domain of the equation: x+1))!=0We get rid of parentheses
x∈R
1/7x-((x/x+1))+5=0
We calculate fractions
x/7x^2+(-((x*7x)/7x^2+5=0
We add all the numbers together, and all the variables
x/7x^2+(-((+x*7x)/7x^2+5=0
We calculate fractions
We do not support expression: x^4
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