(1/7)+2y=1

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Solution for (1/7)+2y=1 equation: 



(1/7)+2y=1

We move all terms to the left:

(1/7)+2y-(1)=0

determiningTheFunctionDomain
2y-1+(1/7)=0

We add all the numbers together, and all the variables

2y-1+(+1/7)=0

We get rid of parentheses

2y-1+1/7=0

We multiply all the terms by the denominator


2y*7+1-1*7=0

We add all the numbers together, and all the variables

2y*7-6=0

Wy multiply elements

14y-6=0

We move all terms containing y to the left, all other terms to the right

14y=6

y=6/14

y=3/7

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