(1/7)(14-7p)-2=-2((1/2p)+3)+6

Solution for (1/7)(14-7p)-2=-2((1/2p)+3)+6 equation:

(1/7)(14-7p)-2=-2((1/2p)+3)+6

We move all terms to the left:

(1/7)(14-7p)-2-(-2((1/2p)+3)+6)=0


Domain of the equation: 7)(14-7p)!=0

p∈R



Domain of the equation: 2p)+3)+6)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(+1/7)(-7p+14)-(-2((+1/2p)+3)+6)-2=0

We multiply parentheses ..

(-7p^2+1/7*14)-(-2((+1/2p)+3)+6)-2=0

We calculate fractions


(-7p^2+2p)/196p^2+()/196p^2-2=0

We multiply all the terms by the denominator


(-7p^2+2p)-2*196p^2+()=0

We add all the numbers together, and all the variables

(-7p^2+2p)-2*196p^2=0

Wy multiply elements

(-7p^2+2p)-392p^2=0

We get rid of parentheses

-7p^2-392p^2+2p=0

We add all the numbers together, and all the variables

-399p^2+2p=0

a = -399; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-399)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-399}=\frac{-4}{-798}
=2/399
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-399}=\frac{0}{-798}
=0
$