(1/6m)+(2/5m)+(4/m)

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Solution for (1/6m)+(2/5m)+(4/m) equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(1/6)*m+(2/5)*m+4/m = 0

17/30*m^1+4*m^-1 = 0

(17/30*m^2+4*m^0)/(m^1) = 0 // * m^2

m^1*(17/30*m^2+4*m^0) = 0

m^1

(17/30)*m^2+4 = 0

(17/30)*m^2+4 = 0

DELTA = 0^2-(4*4*(17/30))

DELTA = -136/15

DELTA < 0

m in { } 

m belongs to the empty set

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