(1/6)y=-5/12

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Solution for (1/6)y=-5/12 equation: 



(1/6)y=-5/12

We move all terms to the left:

(1/6)y-(-5/12)=0



Domain of the equation: 6)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+1/6)y-(-5/12)=0

We multiply parentheses

y^2-(-5/12)=0

We get rid of parentheses

y^2+5/12=0

We multiply all the terms by the denominator


y^2*12+5=0

Wy multiply elements

12y^2+5=0

a = 12; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·12·5
Δ = -240
Delta is less than zero, so there is no solution for the equation

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