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(1/6)x=2x-55
We move all terms to the left:
(1/6)x-(2x-55)=0
Domain of the equation: 6)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/6)x-(2x-55)=0
We multiply parentheses
x^2-(2x-55)=0
We get rid of parentheses
x^2-2x+55=0
a = 1; b = -2; c = +55;
Δ = b2-4ac
Δ = -22-4·1·55
Δ = -216
Delta is less than zero, so there is no solution for the equation
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