(1/6)x+(5/2)=-(1/3)

Solution for (1/6)x+(5/2)=-(1/3) equation:

(1/6)x+(5/2)=-(1/3)

We move all terms to the left:

(1/6)x+(5/2)-(-(1/3))=0


Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/6)x+(+5/2)-(-(+1/3))=0

We multiply parentheses

x^2+(+5/2)-(-(+1/3))=0

We get rid of parentheses

x^2+5/2-(-(+1/3))=0

We calculate fractions


x^2+()/()+()/()=0

We add all the numbers together, and all the variables

x^2+2=0

a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation