(1/6)x+(2/3)=0.25(x-4)

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Solution for (1/6)x+(2/3)=0.25(x-4) equation: 



(1/6)x+(2/3)=0.25(x-4)

We move all terms to the left:

(1/6)x+(2/3)-(0.25(x-4))=0



Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)x-(0.25(x-4))+(+2/3)=0

We multiply parentheses

x^2-(0.25(x-4))+(+2/3)=0

We get rid of parentheses

x^2-(0.25(x-4))+2/3=0

We multiply all the terms by the denominator


x^2*3-((0.25(x-4)))*3+2=0

Wy multiply elements

3x^2-((0.25(x-4)))*3+2=0

We move all terms containing x to the left, all other terms to the right

3x^2-((0.25(x-4)))*3=-2

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