(1/6)p-5=(1/2)p+2

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Solution for (1/6)p-5=(1/2)p+2 equation: 



(1/6)p-5=(1/2)p+2

We move all terms to the left:

(1/6)p-5-((1/2)p+2)=0



Domain of the equation: 6)p!=0

p!=0/1

p!=0

p∈R





Domain of the equation: 2)p+2)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

(+1/6)p-((+1/2)p+2)-5=0

We multiply parentheses

p^2-((+1/2)p+2)-5=0

We multiply all the terms by the denominator


p^2*2)p+2)-((-5*2)p+2)+1=0

We add all the numbers together, and all the variables

p^2*2)p+2)-((-10)p+2)+1=0

Wy multiply elements

2p^3-10)p+2)+1=0

We do not support eppression: p^3

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