(1/6)g+1/3=(1/2)g-1

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Solution for (1/6)g+1/3=(1/2)g-1 equation: 


g in (-oo:+oo)

(1/6)*g+1/3 = (1/2)*g-1 // - (1/2)*g-1

(1/6)*g-((1/2)*g)+1/3+1 = 0

(1/6)*g+(-1/2)*g+1/3+1 = 0

4/3-1/3*g = 0 // - 4/3

-1/3*g = -4/3 // : -1/3

g = -4/3/(-1/3)

g = 4

g = 4

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