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(1/6)(x-36)=(5/6)
We move all terms to the left:
(1/6)(x-36)-((5/6))=0
Domain of the equation: 6)(x-36)!=0We add all the numbers together, and all the variables
x∈R
(+1/6)(x-36)-((+5/6))=0
We multiply parentheses ..
(+x^2+1/6*-36)-((+5/6))=0
We calculate fractions
x^2/()+()/()=0
We add all the numbers together, and all the variables
x^2/()+1=0
We multiply all the terms by the denominator
x^2+1*()=0
We add all the numbers together, and all the variables
x^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{2}=0$
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