(1/6)(x-12)=12

Solution for (1/6)(x-12)=12 equation:

(1/6)(x-12)=12

We move all terms to the left:

(1/6)(x-12)-(12)=0


Domain of the equation: 6)(x-12)!=0

x∈R


We add all the numbers together, and all the variables

(+1/6)(x-12)-12=0

We multiply parentheses ..

(+x^2+1/6*-12)-12=0

We multiply all the terms by the denominator


(+x^2+1-12*6*-12)=0

We get rid of parentheses

x^2+1-12-12*6*=0

We add all the numbers together, and all the variables

x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$