(1/6)(a+12)=-4

Solution for (1/6)(a+12)=-4 equation:

(1/6)(a+12)=-4

We move all terms to the left:

(1/6)(a+12)-(-4)=0


Domain of the equation: 6)(a+12)!=0

a∈R


We add all the numbers together, and all the variables

(+1/6)(a+12)-(-4)=0

We add all the numbers together, and all the variables

(+1/6)(a+12)+4=0

We multiply parentheses ..

(+a^2+1/6*12)+4=0

We multiply all the terms by the denominator


(+a^2+1+4*6*12)=0

We get rid of parentheses

a^2+1+4*6*12=0

We add all the numbers together, and all the variables

a^2+289=0

a = 1; b = 0; c = +289;
Δ = b2-4ac
Δ = 02-4·1·289
Δ = -1156
Delta is less than zero, so there is no solution for the equation