(1/6)(18y+12)-9=-(1/6)(6y-54)

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Solution for (1/6)(18y+12)-9=-(1/6)(6y-54) equation: 



(1/6)(18y+12)-9=-(1/6)(6y-54)

We move all terms to the left:

(1/6)(18y+12)-9-(-(1/6)(6y-54))=0



Domain of the equation: 6)(18y+12)!=0

y∈R





Domain of the equation: 6)(6y-54))!=0

y∈R



We add all the numbers together, and all the variables

(+1/6)(18y+12)-(-(+1/6)(6y-54))-9=0

We multiply parentheses ..

(+18y^2+1/6*12)-(-(+1/6)(6y-54))-9=0

We calculate fractions


((+18y^2+1*6)(6y-54)))/432y^2+()/432y^2-9=0

We can not solve this equation

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