(1/5)x-7=(1/3)x-5

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Solution for (1/5)x-7=(1/3)x-5 equation: 



(1/5)x-7=(1/3)x-5

We move all terms to the left:

(1/5)x-7-((1/3)x-5)=0



Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)x-5)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)x-((+1/3)x-5)-7=0

We multiply parentheses

x^2-((+1/3)x-5)-7=0

We multiply all the terms by the denominator


x^2*3)x-5)-((-7*3)x-5)+1=0

We add all the numbers together, and all the variables

x^2*3)x-5)-((-21)x-5)+1=0

Wy multiply elements

3x^3-21)x-5)+1=0

We do not support expression: x^3

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