(1/5)x+(2/5)x+20=x

Solution for (1/5)x+(2/5)x+20=x equation:

(1/5)x+(2/5)x+20=x

We move all terms to the left:

(1/5)x+(2/5)x+20-(x)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/5)x+(+2/5)x-x+20=0

We add all the numbers together, and all the variables

-1x+(+1/5)x+(+2/5)x+20=0

We multiply parentheses

x^2+2x^2-1x+20=0

We add all the numbers together, and all the variables

3x^2-1x+20=0

a = 3; b = -1; c = +20;
Δ = b2-4ac
Δ = -12-4·3·20
Δ = -239
Delta is less than zero, so there is no solution for the equation