(1/5)x+(1/7)x=0

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Solution for (1/5)x+(1/7)x=0 equation: 



(1/5)x+(1/7)x=0



Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)x+(+1/7)x=0

We multiply parentheses

x^2+x^2=0

We add all the numbers together, and all the variables

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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