(1/5)t+(5/6)=(4/6)-t

Solution for (1/5)t+(5/6)=(4/6)-t equation:

(1/5)t+(5/6)=(4/6)-t

We move all terms to the left:

(1/5)t+(5/6)-((4/6)-t)=0


Domain of the equation: 5)t!=0

t!=0/1

t!=0

t∈R



Domain of the equation: 6)-t)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

(+1/5)t-((+4/6)-t)+(+5/6)=0

We multiply parentheses

t^2-((+4/6)-t)+(+5/6)=0

We get rid of parentheses

t^2-((+4/6)-t)+5/6=0

We calculate fractions


t^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{2}=0$