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x in (-oo:+oo)
(1/5)*sin(5*x) = 0
1/5 = 0
1/5 = 0
x belongs to the empty set
sin(5*x) = 0
sin(5*x) = 0 <=> 5*x = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
5*x-t_1 = 0
5*x-t_1 = 0 // + t_1
5*x = t_1 // : 5
x = t_1/5
x = pi*k_1/5 i k_1 należy do I
(1/5)*sin(5*x) = 0 <=> 1/5 = 0 or (1/5)*sin(5*x) = 0 <=> sin(5*x) = 0
x = pi*k_1/5
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