(1/5)+(7/5a)=4/a

Solution for (1/5)+(7/5a)=4/a equation:

(1/5)+(7/5a)=4/a

We move all terms to the left:

(1/5)+(7/5a)-(4/a)=0


Domain of the equation: 5a)!=0

a!=0/1

a!=0

a∈R



Domain of the equation: a)!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

(+7/5a)-(+4/a)+(+1/5)=0

We get rid of parentheses

7/5a-4/a+1/5=0

We calculate fractions


7a/125a^2+(-500a)/125a^2+a/125a^2=0

We multiply all the terms by the denominator


7a+(-500a)+a=0

We add all the numbers together, and all the variables

8a+(-500a)=0

We get rid of parentheses

8a-500a=0

We add all the numbers together, and all the variables

-492a=0

a=0/-492

a=0

Równanie nie ma rozwiązania