(1/5)*m=7/8

Solution for (1/5)*m=7/8 equation:

(1/5)*m=7/8

We move all terms to the left:

(1/5)*m-(7/8)=0


Domain of the equation: 5)*m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+1/5)*m-(+7/8)=0

We multiply parentheses

m^2-(+7/8)=0

We get rid of parentheses

m^2-7/8=0

We multiply all the terms by the denominator


m^2*8-7=0

Wy multiply elements

8m^2-7=0

a = 8; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·8·(-7)
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{14}}{2*8}=\frac{0-4\sqrt{14}}{16}
=-\frac{4\sqrt{14}}{16}
=-\frac{\sqrt{14}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{14}}{2*8}=\frac{0+4\sqrt{14}}{16}
=\frac{4\sqrt{14}}{16}
=\frac{\sqrt{14}}{4}
$