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x in (-oo:+oo)
(1/5)*(x-5)*(x-1) = 0
1/5*(x-5)*(x-1) = 0
( 1/5 )
1/5 = 0
x belongs to the empty set
( x-1 )
x-1 = 0 // + 1
x = 1
( x-5 )
x-5 = 0 // + 5
x = 5
x in { 1, 5 }
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