(1/4*2x)+7x=2x-(1/4*2x)+36

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Solution for (1/4*2x)+7x=2x-(1/4*2x)+36 equation: 



(1/4*2x)+7x=2x-(1/4*2x)+36

We move all terms to the left:

(1/4*2x)+7x-(2x-(1/4*2x)+36)=0



Domain of the equation: 4*2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4*2x)+36)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/4*2x)+7x-(2x-(+1/4*2x)+36)=0

We add all the numbers together, and all the variables

7x+(+1/4*2x)-(2x-(+1/4*2x)+36)=0

We get rid of parentheses

7x+1/4*2x-(2x-(+1/4*2x)+36)=0

We calculate fractions


7x+16x/256x^2+(-(2x-(+1*4*2x)/256x^2=0

We multiply all the terms by the denominator


7x*256x^2+16x+(-(2x-(+1*4*2x)=0



We calculate terms in parentheses: +(-(2x-(+1*4*2x), so:

-(2x-(+1*4*2x



We add all the numbers together, and all the variables

16x+7x*256x^2+(-(2x-(+1*4*2x)=0

Wy multiply elements

1792x^3+16x+(-(2x-(+1*4*2x)=0



We calculate terms in parentheses: +(-(2x-(+1*4*2x), so:

-(2x-(+1*4*2x



We do not support expression: x^3

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