(1/4)y+1=64

Solution for (1/4)y+1=64 equation:

(1/4)y+1=64

We move all terms to the left:

(1/4)y+1-(64)=0


Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+1/4)y+1-64=0

We add all the numbers together, and all the variables

(+1/4)y-63=0

We multiply parentheses

y^2-63=0

a = 1; b = 0; c = -63;
Δ = b2-4ac
Δ = 02-4·1·(-63)
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{7}}{2*1}=\frac{0-6\sqrt{7}}{2}
=-\frac{6\sqrt{7}}{2}
=-3\sqrt{7}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{7}}{2*1}=\frac{0+6\sqrt{7}}{2}
=\frac{6\sqrt{7}}{2}
=3\sqrt{7}
$