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(1/4)(y+5)+6=(1/3)(4y-1)-13
We move all terms to the left:
(1/4)(y+5)+6-((1/3)(4y-1)-13)=0
Domain of the equation: 4)(y+5)!=0
y∈R
Domain of the equation: 3)(4y-1)-13)!=0We add all the numbers together, and all the variables
y∈R
(+1/4)(y+5)-((+1/3)(4y-1)-13)+6=0
We multiply parentheses ..
(+y^2+1/4*5)-((+1/3)(4y-1)-13)+6=0
We calculate fractions
((+y^2+1*3)(4y-1))/60y^2+()/60y^2+6=0
We multiply all the terms by the denominator
((+y^2+1*3)(4y-1))+6*60y^2+()=0
We calculate terms in parentheses: +((+y^2+1*3)(4y-1)), so:We add all the numbers together, and all the variables
(+y^2+1*3)(4y-1)
((+y^2+1*3)(4y-1))+6*60y^2=0
Wy multiply elements
((+y^2+1*3)(4y-1))+360y^2=0
We calculate terms in parentheses: +((+y^2+1*3)(4y-1)), so:We add all the numbers together, and all the variables
(+y^2+1*3)(4y-1)
360y^2+((+y^2+1*3)(4y-1))=0
We calculate terms in parentheses: +((+y^2+1*3)(4y-1)), so:
(+y^2+1*3)(4y-1)
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(+y^2+1*3)(4y-1)
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(+y^2+1*3)(4y-1)
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(+y^2+1*3)(4y-1)
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(+y^2+1*3)(4y-1)
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(+y^2+1*3)(4y-1)
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(+y^2+1*3)(4y-1)
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(+y^2+1*3)(4y-1)
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