(1/4)(n-6)=(1/4)n-(3/2)

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Solution for (1/4)(n-6)=(1/4)n-(3/2) equation: 


n in (-oo:+oo)

(1/4)*(n-6) = (1/4)*n-(3/2) // - (1/4)*n-(3/2)

(1/4)*(n-6)-((1/4)*n)+3/2 = 0

(1/4)*(n-6)+(-1/4)*n+3/2 = 0

1/4*(n-6)-n/4+3/2 = 0

(1/4*2*4*(n-6))/(2*4)+(2*(-n))/(2*4)+(3*4)/(2*4) = 0

1/4*2*4*(n-6)+2*(-n)+3*4 = 0

12-12 = 0

0 = 0

0/(2*4) = 0

0/(2*4) = 0 // * 2*4

0 = 0

n belongs to the empty set

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