(1/4)(2-y)=1

Solution for (1/4)(2-y)=1 equation:

(1/4)(2-y)=1

We move all terms to the left:

(1/4)(2-y)-(1)=0


Domain of the equation: 4)(2-y)!=0

y∈R


We add all the numbers together, and all the variables

(+1/4)(-1y+2)-1=0

We multiply parentheses ..

(-1y^2+1/4*2)-1=0

We multiply all the terms by the denominator


(-1y^2+1-1*4*2)=0

We get rid of parentheses

-1y^2+1-1*4*2=0

We add all the numbers together, and all the variables

-1y^2-7=0

a = -1; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·(-1)·(-7)
Δ = -28
Delta is less than zero, so there is no solution for the equation