(1/3y)+(2/3y)-42=98

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Solution for (1/3y)+(2/3y)-42=98 equation: 



(1/3y)+(2/3y)-42=98

We move all terms to the left:

(1/3y)+(2/3y)-42-(98)=0



Domain of the equation: 3y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+1/3y)+(+2/3y)-42-98=0

We add all the numbers together, and all the variables

(+1/3y)+(+2/3y)-140=0

We get rid of parentheses

1/3y+2/3y-140=0

We multiply all the terms by the denominator


-140*3y+1+2=0

We add all the numbers together, and all the variables

-140*3y+3=0

Wy multiply elements

-420y+3=0

We move all terms containing y to the left, all other terms to the right

-420y=-3

y=-3/-420

y=1/140

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