(1/3x)-9=14x-7-13x

Solution for (1/3x)-9=14x-7-13x equation:

(1/3x)-9=14x-7-13x

We move all terms to the left:

(1/3x)-9-(14x-7-13x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/3x)-(x-7)-9=0

We get rid of parentheses

1/3x-x+7-9=0

We multiply all the terms by the denominator


-x*3x+7*3x-9*3x+1=0

Wy multiply elements

-3x^2+21x-27x+1=0

We add all the numbers together, and all the variables

-3x^2-6x+1=0

a = -3; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·(-3)·1
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{3}}{2*-3}=\frac{6-4\sqrt{3}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{3}}{2*-3}=\frac{6+4\sqrt{3}}{-6}
$