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(1/3x)-5+171=x
We move all terms to the left:
(1/3x)-5+171-(x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/3x)-x-5+171=0
We add all the numbers together, and all the variables
-1x+(+1/3x)+166=0
We get rid of parentheses
-1x+1/3x+166=0
We multiply all the terms by the denominator
-1x*3x+166*3x+1=0
Wy multiply elements
-3x^2+498x+1=0
a = -3; b = 498; c = +1;
Δ = b2-4ac
Δ = 4982-4·(-3)·1
Δ = 248016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{248016}=\sqrt{16*15501}=\sqrt{16}*\sqrt{15501}=4\sqrt{15501}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(498)-4\sqrt{15501}}{2*-3}=\frac{-498-4\sqrt{15501}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(498)+4\sqrt{15501}}{2*-3}=\frac{-498+4\sqrt{15501}}{-6} $
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