(1/3x)+(3/2x)=11

Solution for (1/3x)+(3/2x)=11 equation:

(1/3x)+(3/2x)=11

We move all terms to the left:

(1/3x)+(3/2x)-(11)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/3x)+(+3/2x)-11=0

We get rid of parentheses

1/3x+3/2x-11=0

We calculate fractions


2x/6x^2+9x/6x^2-11=0

We multiply all the terms by the denominator


2x+9x-11*6x^2=0

We add all the numbers together, and all the variables

11x-11*6x^2=0

Wy multiply elements

-66x^2+11x=0

a = -66; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-66)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-66}=\frac{-22}{-132}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-66}=\frac{0}{-132}
=0
$