(1/3x)+(1/2x)=1/6-1/x

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Solution for (1/3x)+(1/2x)=1/6-1/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*x+(1/2)*x = 1/6-(1/x) // - 1/6-(1/x)

(1/3)*x+(1/2)*x+1/x-(1/6) = 0

(1/3)*x+(1/2)*x+1/x-1/6 = 0

5/6*x^1+1*x^-1-1/6*x^0 = 0

(5/6*x^2-1/6*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(5/6*x^2-1/6*x^1+1*x^0) = 0

x^1

(5/6)*x^2+(-1/6)*x+1 = 0

(5/6)*x^2+(-1/6)*x+1 = 0

DELTA = (-1/6)^2-(1*4*(5/6))

DELTA = -119/36

DELTA < 0

x in { } 

x belongs to the empty set

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