(1/3n+12)=(2n-3)

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Solution for (1/3n+12)=(2n-3) equation: 



(1/3n+12)=(2n-3)

We move all terms to the left:

(1/3n+12)-((2n-3))=0



Domain of the equation: 3n+12)!=0

n∈R



We get rid of parentheses

1/3n-((2n-3))+12=0

We multiply all the terms by the denominator


-(((2n-3)))*3n+12*3n+1=0

Wy multiply elements

-(((2n-3)))*3n+36n+1=0

We add all the numbers together, and all the variables

36n-(((2n-3)))*3n+1=0

We move all terms containing n to the left, all other terms to the right

36n-(((2n-3)))*3n=-1

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