(1/3)y+10=(1/7)y

Solution for (1/3)y+10=(1/7)y equation:

(1/3)y+10=(1/7)y

We move all terms to the left:

(1/3)y+10-((1/7)y)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R



Domain of the equation: 7)y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+1/3)y-((+1/7)y)+10=0

We multiply parentheses

y^2-((+1/7)y)+10=0

We multiply all the terms by the denominator


y^2*7)y)-((+10*7)y)+1=0

We add all the numbers together, and all the variables

y^2*7)y)-(70y)+1=0

We add all the numbers together, and all the variables

y^2*7)y)-70y+1=0

Wy multiply elements

7y^3=0

We do not support eypression: y^3