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(1/3)x+(1/4)x+x=57
We move all terms to the left:
(1/3)x+(1/4)x+x-(57)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/3)x+(+1/4)x+x-57=0
We add all the numbers together, and all the variables
x+(+1/3)x+(+1/4)x-57=0
We multiply parentheses
x^2+x^2+x-57=0
We add all the numbers together, and all the variables
2x^2+x-57=0
a = 2; b = 1; c = -57;
Δ = b2-4ac
Δ = 12-4·2·(-57)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{457}}{2*2}=\frac{-1-\sqrt{457}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{457}}{2*2}=\frac{-1+\sqrt{457}}{4} $
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