(1/3)+(2/3)m=(2/3)m+(-2/3)

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Solution for (1/3)+(2/3)m=(2/3)m+(-2/3) equation: 


m in (-oo:+oo)

(2/3)*m+1/3 = (2/3)*m-2/3 // - (2/3)*m-2/3

(2/3)*m-((2/3)*m)+1/3-(-2/3) = 0

(2/3)*m+(-2/3)*m+1/3+2/3 = 0

1 = 0

m belongs to the empty set

m belongs to the empty set

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