(1/3)*x-4=(2/3)*(3*x-2)

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Solution for (1/3)*x-4=(2/3)*(3*x-2) equation:



(1/3)*x-4=(2/3)(3x-2)
We move all terms to the left:
(1/3)*x-4-((2/3)(3x-2))=0
Domain of the equation: 3)*x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3)(3x-2))!=0
x∈R
We add all the numbers together, and all the variables
(+1/3)*x-((+2/3)(3x-2))-4=0
We multiply parentheses
x^2-((+2/3)(3x-2))-4=0
We multiply parentheses ..
x^2-((+6x^2+2/3*-2))-4=0
We multiply all the terms by the denominator
6x^2+x^2*3*+2-2))-((-4*3*-2))=0
We add all the numbers together, and all the variables
6x^2+x^2*3*+2-2))-(24)=0
We add all the numbers together, and all the variables
6x^2+x^2*3*=0
Wy multiply elements
6x^2+3x^3=0
We do not support expression: x^3

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