(1/3)(x+3)=(1/6)(2x+6)

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Solution for (1/3)(x+3)=(1/6)(2x+6) equation: 


x in (-oo:+oo)

(1/3)*(x+3) = (1/6)*(2*x+6) // - (1/6)*(2*x+6)

(1/3)*(x+3)-((1/6)*(2*x+6)) = 0

(1/3)*(x+3)+(-1/6)*(2*x+6) = 0

1/3*(x+3)-1/6*(2*x+6) = 0

1/3*(x+3)-1/6*(2*x+6) = 0

0 = 0

0 = 0

x belongs to the empty set

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