(1/3)(x+3)=(1/3)(2x+1)

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Solution for (1/3)(x+3)=(1/3)(2x+1) equation: 



(1/3)(x+3)=(1/3)(2x+1)

We move all terms to the left:

(1/3)(x+3)-((1/3)(2x+1))=0



Domain of the equation: 3)(x+3)!=0

x∈R





Domain of the equation: 3)(2x+1))!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)(x+3)-((+1/3)(2x+1))=0

We multiply parentheses ..

(+x^2+1/3*3)-((+1/3)(2x+1))=0

We calculate fractions


((+x^2+1*3)(2x+1)))/27x^2+()/27x^2=0

We can not solve this equation

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