(1/3)(x+1)=2

Solution for (1/3)(x+1)=2 equation:

(1/3)(x+1)=2

We move all terms to the left:

(1/3)(x+1)-(2)=0


Domain of the equation: 3)(x+1)!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)(x+1)-2=0

We multiply parentheses ..

(+x^2+1/3*1)-2=0

We multiply all the terms by the denominator


(+x^2+1-2*3*1)=0

We get rid of parentheses

x^2+1-2*3*1=0

We add all the numbers together, and all the variables

x^2-5=0

a = 1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·1·(-5)
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{5}}{2*1}=\frac{0-2\sqrt{5}}{2}
=-\frac{2\sqrt{5}}{2}
=-\sqrt{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{5}}{2*1}=\frac{0+2\sqrt{5}}{2}
=\frac{2\sqrt{5}}{2}
=\sqrt{5}
$