(1/3)(x)+(1/3)(19-x)=1

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Solution for (1/3)(x)+(1/3)(19-x)=1 equation: 


x in (-oo:+oo)

(1/3)*(19-x)+(1/3)*x = 1 // - 1

(1/3)*(19-x)+(1/3)*x-1 = 0

1/3*(19-x)+x/3-1 = 0

(1/3*3*(19-x))/3+x/3+(-1*3)/3 = 0

1/3*3*(19-x)+x-1*3 = 0

19-3 = 0

16 = 0

16/3 = 0

16/3 = 0 // * 3

16 = 0

x belongs to the empty set

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